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Magnetism, EMI & AC

Biot–Savart and Ampere's laws, forces on moving charges and current-carrying conductors, the moving coil galvanometer and its conversions, magnetism and matter, Faraday's and Lenz's laws, self and mutual inductance, AC circuits with resonance and power factor, transformers and electromagnetic waves.

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1Biot–Savart law and Ampere's circuital law8 min read+15 XP

Moving charges create magnetic fields; Biot–Savart gives the field of each small current element, and Ampere's law gives the field directly when the current distribution is symmetric.

How it's asked: Field at the centre and on the axis of a circular loop, field of a long straight wire, field inside a solenoid and toroid, and direction by the right-hand rule.

Why this is true

A small current element I dl produces a field proportional to I dl sinθ/r², perpendicular to both dl and the line to the point — so there is no field along the wire's own line. Adding these contributions around a circular loop, every element is at the same distance from the centre and contributes in the same direction, giving μ₀I/2R. For long straight wires and solenoids, Ampere's law is easier: the line integral of B around a closed loop equals μ₀ times the current threading it. Around a long wire B is the same on a circle, giving μ₀I/2πr; inside a long solenoid the field is uniform and nearly zero outside, so B = μ₀nI. A toroid is a solenoid bent into a ring, so its field is confined inside the core.

Key points

Key formulae

  • Biot–Savart

    dB = (μ₀/4π) I dl sinθ/r²

  • Straight wire

    B = μ₀I/(2πr)

  • Circular loop (centre)

    B = μ₀NI/(2R)

  • Ampere's law

    ∮B·dl = μ₀I(enclosed)

  • Solenoid

    B = μ₀nI

  • Toroid

    B = μ₀NI/(2πr)

Magnetic fields of standard current distributions

SourceFieldDepends on
Long straight wireμ₀I/2πr1/r
Circular loop, centreμ₀NI/2R1/R
Circular loop, far on axisμ₀NIR²/2x³1/x³ (dipole-like)
Long solenoid, insideμ₀nITurns per length only
Toroid, inside coreμ₀NI/2πrMean radius

Common traps

  • In B = μ₀nI, n is turns per metre, not the total number of turns.
  • A point on the line of a straight current element gets no field from it (sinθ = 0).

Worked example

A solenoid 0.5 m long has 500 turns and carries 2 A. Find the magnetic field inside it.

High-yield

Wire μ₀I/2πr; loop centre μ₀NI/2R; solenoid μ₀nI; toroid μ₀NI/2πr.

Quick check

Q1.The magnetic field 5 cm from a long straight wire carrying 10 A is:

Q2.The magnetic field inside a long ideal solenoid is:

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